11331040443001 has 4 divisors (see below), whose sum is σ = 11331213715600. Its totient is φ = 11330867170404.

The previous prime is 11331040442999. The next prime is 11331040443007. The reversal of 11331040443001 is 10034404013311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331040443001 - 2¹ = 11331040442999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331040443007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86538171 + ... + 86669008.

It is an arithmetic number, because the mean of its divisors is an integer number (2832803428900).

Almost surely, 2^{11331040443001} is an apocalyptic number.

It is an amenable number.

11331040443001 is a deficient number, since it is larger than the sum of its proper divisors (173272599).

11331040443001 is an equidigital number, since it uses as much as digits as its factorization.

11331040443001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173272598.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11331040443001 its reverse (10034404013311), we get a palindrome (21365444456312).

The spelling of 11331040443001 in words is "eleven trillion, three hundred thirty-one billion, forty million, four hundred forty-three thousand, one".