Base | Representation |
---|---|
bin | 1010010011100011101011… |
… | …0011010001000010111011 |
3 | 1111010020120112222212121202 |
4 | 2210320322303101002323 |
5 | 2441122103210311124 |
6 | 40033235025124415 |
7 | 2246434321626251 |
oct | 244707263210273 |
9 | 44106515885552 |
10 | 11331110244539 |
11 | 3679551371408 |
12 | 1330065a8970b |
13 | 642699644687 |
14 | 2b260036a5d1 |
15 | 149b3519d5ae |
hex | a4e3acd10bb |
11331110244539 has 2 divisors, whose sum is σ = 11331110244540. Its totient is φ = 11331110244538.
The previous prime is 11331110244533. The next prime is 11331110244577. The reversal of 11331110244539 is 93544201113311.
11331110244539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (11331110244577) can be obtained adding 11331110244539 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331110244539 - 220 = 11331109195963 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331110244533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665555122269 + 5665555122270.
It is an arithmetic number, because the mean of its divisors is an integer number (5665555122270).
Almost surely, 211331110244539 is an apocalyptic number.
11331110244539 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331110244539 is an equidigital number, since it uses as much as digits as its factorization.
11331110244539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 38.
The spelling of 11331110244539 in words is "eleven trillion, three hundred thirty-one billion, one hundred ten million, two hundred forty-four thousand, five hundred thirty-nine".
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