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11331110331283 is a prime number
BaseRepresentation
bin1010010011100011101011…
…0011100110001110010011
31111010020120120011021121111
42210320322303212032103
52441122103221100113
640033235031034151
72246434322440201
oct244707263461623
944106516137544
1011331110331283
1136795514205a6
121330065b0b957
13642699674cc2
142b2600390071
15149b351b913d
hexa4e3ace6393

11331110331283 has 2 divisors, whose sum is σ = 11331110331284. Its totient is φ = 11331110331282.

The previous prime is 11331110331271. The next prime is 11331110331287. The reversal of 11331110331283 is 38213301113311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331110331283 is a prime.

It is a super-2 number, since 2×113311103312832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331110331287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665555165641 + 5665555165642.

It is an arithmetic number, because the mean of its divisors is an integer number (5665555165642).

Almost surely, 211331110331283 is an apocalyptic number.

11331110331283 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331110331283 is an equidigital number, since it uses as much as digits as its factorization.

11331110331283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

Adding to 11331110331283 its reverse (38213301113311), we get a palindrome (49544411444594).

The spelling of 11331110331283 in words is "eleven trillion, three hundred thirty-one billion, one hundred ten million, three hundred thirty-one thousand, two hundred eighty-three".