Base | Representation |
---|---|
bin | 11001110000111001001100… |
… | …100010001011101001110001 |
3 | 112212012102210011111011022121 |
4 | 121300321030202023221301 |
5 | 104322442123433411423 |
6 | 1040554223400434241 |
7 | 32603312652565114 |
oct | 3160711442135161 |
9 | 485172704434277 |
10 | 113311111232113 |
11 | 33116a77304323 |
12 | 10860551a78981 |
13 | 4b2c265901702 |
14 | 1dda40392257b |
15 | d17736d2745d |
hex | 670e4c88ba71 |
113311111232113 has 8 divisors (see below), whose sum is σ = 119511980884800. Its totient is φ = 107133954275088.
The previous prime is 113311111232107. The next prime is 113311111232171. The reversal of 113311111232113 is 311232111113311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113311111232113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113311111232413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5928164098 + ... + 5928183211.
It is an arithmetic number, because the mean of its divisors is an integer number (14938997610600).
Almost surely, 2113311111232113 is an apocalyptic number.
It is an amenable number.
113311111232113 is a deficient number, since it is larger than the sum of its proper divisors (6200869652687).
113311111232113 is a wasteful number, since it uses less digits than its factorization.
113311111232113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11856347831.
The product of its digits is 324, while the sum is 25.
Adding to 113311111232113 its reverse (311232111113311), we get a palindrome (424543222345424).
The spelling of 113311111232113 in words is "one hundred thirteen trillion, three hundred eleven billion, one hundred eleven million, two hundred thirty-two thousand, one hundred thirteen".
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