Base | Representation |
---|---|
bin | 10000011111010010101… |
… | …100101000001011011111 |
3 | 11000022202110211202100002 |
4 | 100133102230220023133 |
5 | 122031102444004434 |
6 | 2224313311524515 |
7 | 144602361150062 |
oct | 20372254501337 |
9 | 4008673752302 |
10 | 1133111313119 |
11 | 3a7605883685 |
12 | 16373082973b |
13 | 82b0c929846 |
14 | 3cbb2c128d9 |
15 | 1e71c80a57e |
hex | 107d2b282df |
1133111313119 has 2 divisors, whose sum is σ = 1133111313120. Its totient is φ = 1133111313118.
The previous prime is 1133111313109. The next prime is 1133111313137. The reversal of 1133111313119 is 9113131113311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133111313119 is a prime.
It is a super-2 number, since 2×11331113131192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1133111313091 and 1133111313100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133111313109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566555656559 + 566555656560.
It is an arithmetic number, because the mean of its divisors is an integer number (566555656560).
Almost surely, 21133111313119 is an apocalyptic number.
1133111313119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133111313119 is an equidigital number, since it uses as much as digits as its factorization.
1133111313119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 729, while the sum is 29.
The spelling of 1133111313119 in words is "one trillion, one hundred thirty-three billion, one hundred eleven million, three hundred thirteen thousand, one hundred nineteen".
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