1133112123133 has 4 divisors (see below), whose sum is σ = 1133114600320. Its totient is φ = 1133109645948.

The previous prime is 1133112123131. The next prime is 1133112123137. The reversal of 1133112123133 is 3313212113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133112123133 - 2¹ = 1133112123131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133112123098 and 1133112123107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133112123131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 330573 + ... + 1541266.

It is an arithmetic number, because the mean of its divisors is an integer number (283278650080).

Almost surely, 2^{1133112123133} is an apocalyptic number.

It is an amenable number.

1133112123133 is a deficient number, since it is larger than the sum of its proper divisors (2477187).

1133112123133 is an equidigital number, since it uses as much as digits as its factorization.

1133112123133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2477186.

The product of its digits is 972, while the sum is 25.

Adding to 1133112123133 its reverse (3313212113311), we get a palindrome (4446324236444).

The spelling of 1133112123133 in words is "one trillion, one hundred thirty-three billion, one hundred twelve million, one hundred twenty-three thousand, one hundred thirty-three".