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11331122011981 is a prime number
BaseRepresentation
bin1010010011100011101110…
…0000001001111101001101
31111010020121101010201111221
42210320323200021331031
52441122114213340411
640033240125243341
72246434523636542
oct244707340117515
944106541121457
1011331122011981
113679557a79472
121330069a03551
1364269bc04865
142b2601b50bc9
15149b36225071
hexa4e3b809f4d

11331122011981 has 2 divisors, whose sum is σ = 11331122011982. Its totient is φ = 11331122011980.

The previous prime is 11331122011961. The next prime is 11331122012107. The reversal of 11331122011981 is 18911022113311.

11331122011981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11317505222500 + 13616789481 = 3364150^2 + 116691^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331122011981 - 25 = 11331122011949 is a prime.

It is a super-2 number, since 2×113311220119812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331122011961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561005990 + 5665561005991.

It is an arithmetic number, because the mean of its divisors is an integer number (5665561005991).

Almost surely, 211331122011981 is an apocalyptic number.

It is an amenable number.

11331122011981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331122011981 is an equidigital number, since it uses as much as digits as its factorization.

11331122011981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 34.

The spelling of 11331122011981 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, eleven thousand, nine hundred eighty-one".