Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …0010111001110111010111 |
3 | 1111010020121201101102101112 |
4 | 2210320323302321313113 |
5 | 2441122121443124212 |
6 | 40033240422445235 |
7 | 2246434613466512 |
oct | 244707362716727 |
9 | 44106551342345 |
10 | 11331126926807 |
11 | 367955a826006 |
12 | 133006b59381b |
13 | 64269cc3593c |
14 | 2b260266dd79 |
15 | 149b36896422 |
hex | a4e3bcb9dd7 |
11331126926807 has 2 divisors, whose sum is σ = 11331126926808. Its totient is φ = 11331126926806.
The previous prime is 11331126926797. The next prime is 11331126926843. The reversal of 11331126926807 is 70862962113311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331126926807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331126926107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665563463403 + 5665563463404.
It is an arithmetic number, because the mean of its divisors is an integer number (5665563463404).
Almost surely, 211331126926807 is an apocalyptic number.
11331126926807 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331126926807 is an equidigital number, since it uses as much as digits as its factorization.
11331126926807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 11331126926807 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-six million, nine hundred twenty-six thousand, eight hundred seven".
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