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11331129881249 is a prime number
BaseRepresentation
bin1010010011100011101111…
…1110001011001010100001
31111010020121220221112010022
42210320323332023022201
52441122123222144444
640033241010043225
72246434650553163
oct244707376131241
944106556845108
1011331129881249
1136795614637a2
121330070579515
136426a072b629
142b2602bdc933
15149b36c7b9ee
hexa4e3bf8b2a1

11331129881249 has 2 divisors, whose sum is σ = 11331129881250. Its totient is φ = 11331129881248.

The previous prime is 11331129881191. The next prime is 11331129881261. The reversal of 11331129881249 is 94218892113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11298203238400 + 32926642849 = 3361280^2 + 181457^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331129881249 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11331129881249.

It is not a weakly prime, because it can be changed into another prime (11331129881549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665564940624 + 5665564940625.

It is an arithmetic number, because the mean of its divisors is an integer number (5665564940625).

Almost surely, 211331129881249 is an apocalyptic number.

It is an amenable number.

11331129881249 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331129881249 is an equidigital number, since it uses as much as digits as its factorization.

11331129881249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 746496, while the sum is 53.

The spelling of 11331129881249 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-nine million, eight hundred eighty-one thousand, two hundred forty-nine".