Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1111000000100111100101 |
3 | 1111010020121221100122110111 |
4 | 2210320323333000213211 |
5 | 2441122123301201242 |
6 | 40033241014453021 |
7 | 2246434652454415 |
oct | 244707377004745 |
9 | 44106557318414 |
10 | 11331130100197 |
11 | 36795615a3246 |
12 | 1330070664171 |
13 | 6426a07a719b |
14 | 2b2602c58645 |
15 | 149b36cc1817 |
hex | a4e3bfc09e5 |
11331130100197 has 2 divisors, whose sum is σ = 11331130100198. Its totient is φ = 11331130100196.
The previous prime is 11331130100159. The next prime is 11331130100209. The reversal of 11331130100197 is 79100103113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8165883475201 + 3165246624996 = 2857601^2 + 1779114^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331130100197 - 223 = 11331121711589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331130100107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565050098 + 5665565050099.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565050099).
Almost surely, 211331130100197 is an apocalyptic number.
It is an amenable number.
11331130100197 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130100197 is an equidigital number, since it uses as much as digits as its factorization.
11331130100197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701, while the sum is 31.
The spelling of 11331130100197 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, one hundred thousand, one hundred ninety-seven".
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