11331130113131 has 2 divisors, whose sum is σ = 11331130113132. Its totient is φ = 11331130113130.

The previous prime is 11331130113119. The next prime is 11331130113179. The reversal of 11331130113131 is 13131103113311.

It is a weak prime.

It is an emirp because it is prime and its reverse (13131103113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331130113131 - 2¹⁴ = 11331130096747 is a prime.

It is a super-2 number, since 2×11331130113131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331130113097 and 11331130113106.

It is not a weakly prime, because it can be changed into another prime (11331130113101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565056565 + 5665565056566.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565056566).

Almost surely, 2^{11331130113131} is an apocalyptic number.

11331130113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331130113131 is an equidigital number, since it uses as much as digits as its factorization.

11331130113131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

Adding to 11331130113131 its reverse (13131103113311), we get a palindrome (24462233226442).

The spelling of 11331130113131 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, one hundred thirteen thousand, one hundred thirty-one".