Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1111011001000010000111 |
3 | 1111010020121221112201122021 |
4 | 2210320323333121002013 |
5 | 2441122123312401244 |
6 | 40033241020544011 |
7 | 2246434653352105 |
oct | 244707377310207 |
9 | 44106557481567 |
10 | 11331130200199 |
11 | 3679561661397 |
12 | 13300706b2007 |
13 | 6426a0810864 |
14 | 2b2602c82c75 |
15 | 149b36ce1284 |
hex | a4e3bfd9087 |
11331130200199 has 2 divisors, whose sum is σ = 11331130200200. Its totient is φ = 11331130200198.
The previous prime is 11331130200109. The next prime is 11331130200263. The reversal of 11331130200199 is 99100203113311.
It is a strong prime.
It is an emirp because it is prime and its reverse (99100203113311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331130200199 - 211 = 11331130198151 is a prime.
It is a super-2 number, since 2×113311302001992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331130200109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565100099 + 5665565100100.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565100100).
Almost surely, 211331130200199 is an apocalyptic number.
11331130200199 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130200199 is an equidigital number, since it uses as much as digits as its factorization.
11331130200199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 34.
The spelling of 11331130200199 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, two hundred thousand, one hundred ninety-nine".
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