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11331131101219 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0010110101000000100011
31111010020122000020111121101
42210320330002311000203
52441122124030214334
640033241052135231
72246434664124016
oct244707402650043
944106560214541
1011331131101219
113679562117336
121330070a67517
136426a0a679c7
142b260303937d
15149b36e1d214
hexa4e3c0b5023

11331131101219 has 2 divisors, whose sum is σ = 11331131101220. Its totient is φ = 11331131101218.

The previous prime is 11331131101181. The next prime is 11331131101247. The reversal of 11331131101219 is 91210113113311.

It is an a-pointer prime, because the next prime (11331131101247) can be obtained adding 11331131101219 to its sum of digits (28).

It is a strong prime.

It is an emirp because it is prime and its reverse (91210113113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331131101219 - 215 = 11331131068451 is a prime.

It is a super-2 number, since 2×113311311012192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331131101819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565550609 + 5665565550610.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565550610).

Almost surely, 211331131101219 is an apocalyptic number.

11331131101219 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131101219 is an equidigital number, since it uses as much as digits as its factorization.

11331131101219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 28.

The spelling of 11331131101219 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred one thousand, two hundred nineteen".