1133113112113 has 4 divisors (see below), whose sum is σ = 1133896191040. Its totient is φ = 1132330033188.

The previous prime is 1133113112111. The next prime is 1133113112147. The reversal of 1133113112113 is 3112113113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133113112113 - 2¹ = 1133113112111 is a prime.

It is a super-3 number, since 3×1133113112113³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1133113112111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391537293 + ... + 391540186.

It is an arithmetic number, because the mean of its divisors is an integer number (283474047760).

Almost surely, 2^{1133113112113} is an apocalyptic number.

It is an amenable number.

1133113112113 is a deficient number, since it is larger than the sum of its proper divisors (783078927).

1133113112113 is an equidigital number, since it uses as much as digits as its factorization.

1133113112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 783078926.

The product of its digits is 162, while the sum is 22.

Adding to 1133113112113 its reverse (3112113113311), we get a palindrome (4245226225424).

The spelling of 1133113112113 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred twelve thousand, one hundred thirteen".