Base | Representation |
---|---|
bin | 101101010010011000011… |
… | …001011000100011011111 |
3 | 102000111220111212112100011 |
4 | 231102120121120203133 |
5 | 401442101424111221 |
6 | 10341403544344051 |
7 | 440562030665536 |
oct | 55223031304337 |
9 | 12014814775304 |
10 | 3112113113311 |
11 | a9a9267a1124 |
12 | 423194475027 |
13 | 197617a595c7 |
14 | aa8ac9bb31d |
15 | 55e470e41e1 |
hex | 2d4986588df |
3112113113311 has 4 divisors (see below), whose sum is σ = 3112129783432. Its totient is φ = 3112096443192.
The previous prime is 3112113113309. The next prime is 3112113113341. The reversal of 3112113113311 is 1133113112113.
3112113113311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3112113113311 - 21 = 3112113113309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112113113341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8051820 + ... + 8429473.
It is an arithmetic number, because the mean of its divisors is an integer number (778032445858).
Almost surely, 23112113113311 is an apocalyptic number.
3112113113311 is a deficient number, since it is larger than the sum of its proper divisors (16670121).
3112113113311 is a wasteful number, since it uses less digits than its factorization.
3112113113311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16670120.
The product of its digits is 162, while the sum is 22.
Adding to 3112113113311 its reverse (1133113112113), we get a palindrome (4245226225424).
The spelling of 3112113113311 in words is "three trillion, one hundred twelve billion, one hundred thirteen million, one hundred thirteen thousand, three hundred eleven".
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