1133113112130 has 16 divisors (see below), whose sum is σ = 2719471469184. Its totient is φ = 302163496560.

The previous prime is 1133113112111. The next prime is 1133113112147. The reversal of 1133113112130 is 312113113311.

It is a junction number, because it is equal to n+sod(n) for n = 1133113112097 and 1133113112106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18885218506 + ... + 18885218565.

It is an arithmetic number, because the mean of its divisors is an integer number (169966966824).

Almost surely, 2^{1133113112130} is an apocalyptic number.

1133113112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1133113112130 is an abundant number, since it is smaller than the sum of its proper divisors (1586358357054).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133113112130 is a wasteful number, since it uses less digits than its factorization.

1133113112130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37770437081.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1133113112130 its reverse (312113113311), we get a palindrome (1445226225441).

The spelling of 1133113112130 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred twelve thousand, one hundred thirty".