1133113112223 has 4 divisors (see below), whose sum is σ = 1510817482968. Its totient is φ = 755408741480.

The previous prime is 1133113112207. The next prime is 1133113112273. The reversal of 1133113112223 is 3222113113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133113112223 - 2⁴ = 1133113112207 is a prime.

It is a super-3 number, since 3×1133113112223³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1133113112193 and 1133113112202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133113112273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188852185368 + ... + 188852185373.

It is an arithmetic number, because the mean of its divisors is an integer number (377704370742).

Almost surely, 2^{1133113112223} is an apocalyptic number.

1133113112223 is a deficient number, since it is larger than the sum of its proper divisors (377704370745).

1133113112223 is an equidigital number, since it uses as much as digits as its factorization.

1133113112223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377704370744.

The product of its digits is 648, while the sum is 24.

Adding to 1133113112223 its reverse (3222113113311), we get a palindrome (4355226225534).

The spelling of 1133113112223 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred twelve thousand, two hundred twenty-three".