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11331131132303 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0010111100100110001111
31111010020122000022002020122
42210320330002330212033
52441122124032213203
640033241052535155
72246434664313443
oct244707402744617
944106560262218
1011331131132303
113679562138724
121330070a814bb
136426a0a78bb8
142b2603046823
15149b36e27538
hexa4e3c0bc98f

11331131132303 has 2 divisors, whose sum is σ = 11331131132304. Its totient is φ = 11331131132302.

The previous prime is 11331131132281. The next prime is 11331131132353. The reversal of 11331131132303 is 30323113113311.

11331131132303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30323113113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331131132303 - 28 = 11331131132047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131132353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565566151 + 5665565566152.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565566152).

Almost surely, 211331131132303 is an apocalyptic number.

11331131132303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131132303 is an equidigital number, since it uses as much as digits as its factorization.

11331131132303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 26.

Adding to 11331131132303 its reverse (30323113113311), we get a palindrome (41654244245614).

The spelling of 11331131132303 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred three".