Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010111100110100001001 |
3 | 1111010020122000022010110121 |
4 | 2210320330002330310021 |
5 | 2441122124032230233 |
6 | 40033241052543241 |
7 | 2246434664316154 |
oct | 244707402746411 |
9 | 44106560263417 |
10 | 11331131133193 |
11 | 3679562139363 |
12 | 1330070a81b21 |
13 | 6426a0a79421 |
14 | 2b2603046c9b |
15 | 149b36e2792d |
hex | a4e3c0bcd09 |
11331131133193 has 2 divisors, whose sum is σ = 11331131133194. Its totient is φ = 11331131133192.
The previous prime is 11331131133079. The next prime is 11331131133269. The reversal of 11331131133193 is 39133113113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5929746101449 + 5401385031744 = 2435107^2 + 2324088^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131133193 - 225 = 11331097578761 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331131133293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565566596 + 5665565566597.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565566597).
Almost surely, 211331131133193 is an apocalyptic number.
It is an amenable number.
11331131133193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131133193 is an equidigital number, since it uses as much as digits as its factorization.
11331131133193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6561, while the sum is 34.
The spelling of 11331131133193 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred thirty-three thousand, one hundred ninety-three".
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