Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011001111100110000001 |
3 | 1111010020122000110000222111 |
4 | 2210320330003033212001 |
5 | 2441122124042210423 |
6 | 40033241054335321 |
7 | 2246434665056341 |
oct | 244707403174601 |
9 | 44106560400874 |
10 | 11331131210113 |
11 | 3679562191130 |
12 | 1330070aba541 |
13 | 6426a0aa5440 |
14 | 2b2603066d21 |
15 | 149b36e4060d |
hex | a4e3c0cf981 |
11331131210113 has 32 divisors (see below), whose sum is σ = 13523607175680. Its totient is φ = 9358126525440.
The previous prime is 11331131210111. The next prime is 11331131210219. The reversal of 11331131210113 is 31101213113311.
It is not a de Polignac number, because 11331131210113 - 21 = 11331131210111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331131210111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3661053 + ... + 6005461.
It is an arithmetic number, because the mean of its divisors is an integer number (422612724240).
Almost surely, 211331131210113 is an apocalyptic number.
11331131210113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11331131210113 is a deficient number, since it is larger than the sum of its proper divisors (2192475965567).
11331131210113 is a wasteful number, since it uses less digits than its factorization.
11331131210113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2344969.
The product of its (nonzero) digits is 162, while the sum is 22.
Adding to 11331131210113 its reverse (31101213113311), we get a palindrome (42432344323424).
The spelling of 11331131210113 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred ten thousand, one hundred thirteen".
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