Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011010100101101111111 |
3 | 1111010020122000111002202220 |
4 | 2210320330003110231333 |
5 | 2441122124043343403 |
6 | 40033241055020423 |
7 | 2246434665204465 |
oct | 244707403245577 |
9 | 44106560432686 |
10 | 11331131231103 |
11 | 36795621a5982 |
12 | 1330070b0a713 |
13 | 6426a0ab1b68 |
14 | 2b2603070835 |
15 | 149b36e46953 |
hex | a4e3c0d4b7f |
11331131231103 has 4 divisors (see below), whose sum is σ = 15108174974808. Its totient is φ = 7554087487400.
The previous prime is 11331131231081. The next prime is 11331131231213. The reversal of 11331131231103 is 30113213113311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331131231103 - 28 = 11331131230847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331131231003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888521871848 + ... + 1888521871853.
It is an arithmetic number, because the mean of its divisors is an integer number (3777043743702).
Almost surely, 211331131231103 is an apocalyptic number.
11331131231103 is a deficient number, since it is larger than the sum of its proper divisors (3777043743705).
11331131231103 is an equidigital number, since it uses as much as digits as its factorization.
11331131231103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3777043743704.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 11331131231103 its reverse (30113213113311), we get a palindrome (41444344344414).
The spelling of 11331131231103 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred thirty-one thousand, one hundred three".
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