Base | Representation |
---|---|
bin | 10000011111010010110… |
… | …011100011110100011011 |
3 | 11000022202121021001222212 |
4 | 100133102303203310123 |
5 | 122031103430132032 |
6 | 2224313414505335 |
7 | 144602412455636 |
oct | 20372263436433 |
9 | 4008677231885 |
10 | 1133113130267 |
11 | 3a7606904958 |
12 | 16373136524b |
13 | 82b10114991 |
14 | 3cbb3166c1d |
15 | 1e71ca68bb2 |
hex | 107d2ce3d1b |
1133113130267 has 2 divisors, whose sum is σ = 1133113130268. Its totient is φ = 1133113130266.
The previous prime is 1133113130239. The next prime is 1133113130309. The reversal of 1133113130267 is 7620313113311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1133113130267 - 26 = 1133113130203 is a prime.
It is a super-2 number, since 2×11331131302672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1133113135267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556565133 + 566556565134.
It is an arithmetic number, because the mean of its divisors is an integer number (566556565134).
Almost surely, 21133113130267 is an apocalyptic number.
1133113130267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133113130267 is an equidigital number, since it uses as much as digits as its factorization.
1133113130267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
Adding to 1133113130267 its reverse (7620313113311), we get a palindrome (8753426243578).
The spelling of 1133113130267 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred thirty thousand, two hundred sixty-seven".
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