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11331131330201 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0011101100111010011001
31111010020122000200010201012
42210320330003230322121
52441122124110031301
640033241101103305
72246434666066424
oct244707403547231
944106560603635
1011331131330201
113679562263381
121330070b57b35
136426a0b17cb7
142b26030989bb
15149b36e65ebb
hexa4e3c0ece99

11331131330201 has 2 divisors, whose sum is σ = 11331131330202. Its totient is φ = 11331131330200.

The previous prime is 11331131330147. The next prime is 11331131330243. The reversal of 11331131330201 is 10203313113311.

11331131330201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11079178531600 + 251952798601 = 3328540^2 + 501949^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331131330201 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331131330261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565665100 + 5665565665101.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565665101).

Almost surely, 211331131330201 is an apocalyptic number.

It is an amenable number.

11331131330201 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131330201 is an equidigital number, since it uses as much as digits as its factorization.

11331131330201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331131330201 its reverse (10203313113311), we get a palindrome (21534444443512).

The spelling of 11331131330201 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty thousand, two hundred one".