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11331131999981 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0110010000011011101101
31111010020122001221011110212
42210320330012100123231
52441122124242444411
640033241123312205
72246435004556223
oct244707406203355
944106561834425
1011331131999981
113679562680612
12133007121b665
136426a0cc0b11
142b26031d0b13
15149b3704968b
hexa4e3c1906ed

11331131999981 has 2 divisors, whose sum is σ = 11331131999982. Its totient is φ = 11331131999980.

The previous prime is 11331131999969. The next prime is 11331132000031. The reversal of 11331131999981 is 18999913113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7106175079081 + 4224956920900 = 2665741^2 + 2055470^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331131999981 - 210 = 11331131998957 is a prime.

It is a super-2 number, since 2×113311319999812 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11331131999981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131999281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565999990 + 5665565999991.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565999991).

Almost surely, 211331131999981 is an apocalyptic number.

It is an amenable number.

11331131999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131999981 is an equidigital number, since it uses as much as digits as its factorization.

11331131999981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1417176, while the sum is 59.

The spelling of 11331131999981 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, nine hundred ninety-nine thousand, nine hundred eighty-one".