Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000011101100111 |
3 | 1111010020122001221011122101 |
4 | 2210320330012100131213 |
5 | 2441122124243000403 |
6 | 40033241123312531 |
7 | 2246435004556456 |
oct | 244707406203547 |
9 | 44106561834571 |
10 | 11331132000103 |
11 | 3679562680713 |
12 | 133007121b747 |
13 | 6426a0cc0ba6 |
14 | 2b26031d0b9d |
15 | 149b3704971d |
hex | a4e3c190767 |
11331132000103 has 2 divisors, whose sum is σ = 11331132000104. Its totient is φ = 11331132000102.
The previous prime is 11331132000091. The next prime is 11331132000217. The reversal of 11331132000103 is 30100023113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331132000103 - 29 = 11331131999591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331132060103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000051 + 5665566000052.
It is an arithmetic number, because the mean of its divisors is an integer number (5665566000052).
Almost surely, 211331132000103 is an apocalyptic number.
11331132000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331132000103 is an equidigital number, since it uses as much as digits as its factorization.
11331132000103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11331132000103 its reverse (30100023113311), we get a palindrome (41431155113414).
The spelling of 11331132000103 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one hundred three", and thus it is an aban number.
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