11331132003403 has 2 divisors, whose sum is σ = 11331132003404. Its totient is φ = 11331132003402.

The previous prime is 11331132003397. The next prime is 11331132003409. The reversal of 11331132003403 is 30430023113311.

It is a balanced prime because it is at equal distance from previous prime (11331132003397) and next prime (11331132003409).

It is an emirp because it is prime and its reverse (30430023113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331132003403 - 2⁵ = 11331132003371 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331132003409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566001701 + 5665566001702.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566001702).

Almost surely, 2^{11331132003403} is an apocalyptic number.

11331132003403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132003403 is an equidigital number, since it uses as much as digits as its factorization.

11331132003403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11331132003403 its reverse (30430023113311), we get a palindrome (41761155116714).

The spelling of 11331132003403 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, three thousand, four hundred three".