11331132013023 has 4 divisors (see below), whose sum is σ = 15108176017368. Its totient is φ = 7554088008680.

The previous prime is 11331132013001. The next prime is 11331132013039. The reversal of 11331132013023 is 32031023113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331132013023 - 2⁹ = 11331132012511 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331132012984 and 11331132013002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331132013093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888522002168 + ... + 1888522002173.

It is an arithmetic number, because the mean of its divisors is an integer number (3777044004342).

Almost surely, 2^{11331132013023} is an apocalyptic number.

11331132013023 is a deficient number, since it is larger than the sum of its proper divisors (3777044004345).

11331132013023 is an equidigital number, since it uses as much as digits as its factorization.

11331132013023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3777044004344.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 11331132013023 its reverse (32031023113311), we get a palindrome (43362155126334).

The spelling of 11331132013023 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, thirteen thousand, twenty-three".