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113311713196639 is a prime number
BaseRepresentation
bin11001110000111001110000…
…011010011111101001011111
3112212012111100010012010102001
4121300321300122133221133
5104322444342034243024
61040554403222543131
732603333612315536
oct3160716032375137
9485174303163361
10113311713196639
1133117256084171
121086069b597aa7
134b2c330537539
141dda45d85b31d
15d1776ead2244
hex670e7069fa5f

113311713196639 has 2 divisors, whose sum is σ = 113311713196640. Its totient is φ = 113311713196638.

The previous prime is 113311713196631. The next prime is 113311713196699. The reversal of 113311713196639 is 936691317113311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113311713196639 - 23 = 113311713196631 is a prime.

It is a super-3 number, since 3×1133117131966393 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113311713196639.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113311713196631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655856598319 + 56655856598320.

It is an arithmetic number, because the mean of its divisors is an integer number (56655856598320).

Almost surely, 2113311713196639 is an apocalyptic number.

113311713196639 is a deficient number, since it is larger than the sum of its proper divisors (1).

113311713196639 is an equidigital number, since it uses as much as digits as its factorization.

113311713196639 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1653372, while the sum is 55.

The spelling of 113311713196639 in words is "one hundred thirteen trillion, three hundred eleven billion, seven hundred thirteen million, one hundred ninety-six thousand, six hundred thirty-nine".