113312000041 has 2 divisors, whose sum is σ = 113312000042. Its totient is φ = 113312000040.

The previous prime is 113312000033. The next prime is 113312000051. The reversal of 113312000041 is 140000213311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65702505625 + 47609494416 = 256325^2 + 218196^2 .

It is a cyclic number.

It is not a de Polignac number, because 113312000041 - 2³ = 113312000033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113311999979 and 113312000024.

It is not a weakly prime, because it can be changed into another prime (113312000051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656000020 + 56656000021.

It is an arithmetic number, because the mean of its divisors is an integer number (56656000021).

Almost surely, 2^113312000041 is an apocalyptic number.

It is an amenable number.

113312000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

113312000041 is an equidigital number, since it uses as much as digits as its factorization.

113312000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 113312000041 its reverse (140000213311), we get a palindrome (253312213352).

The spelling of 113312000041 in words is "one hundred thirteen billion, three hundred twelve million, forty-one", and thus it is an aban number.