Base | Representation |
---|---|
bin | 1010010011100100011000… |
… | …0111111111010010010111 |
3 | 1111010021001210110221110112 |
4 | 2210321012013333102113 |
5 | 2441123000324214244 |
6 | 40033305533113235 |
7 | 2246442116506532 |
oct | 244710607772227 |
9 | 44107053427415 |
10 | 11331300226199 |
11 | 3679639631448 |
12 | 13300b962881b |
13 | 6426c9b01965 |
14 | 2b261b6a1a19 |
15 | 149b46bc939e |
hex | a4e461ff497 |
11331300226199 has 2 divisors, whose sum is σ = 11331300226200. Its totient is φ = 11331300226198.
The previous prime is 11331300226121. The next prime is 11331300226237. The reversal of 11331300226199 is 99162200313311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331300226199 - 224 = 11331283448983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331300226699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665650113099 + 5665650113100.
It is an arithmetic number, because the mean of its divisors is an integer number (5665650113100).
Almost surely, 211331300226199 is an apocalyptic number.
11331300226199 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331300226199 is an equidigital number, since it uses as much as digits as its factorization.
11331300226199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 11331300226199 in words is "eleven trillion, three hundred thirty-one billion, three hundred million, two hundred twenty-six thousand, one hundred ninety-nine".
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