Base | Representation |
---|---|
bin | 1010010011100100011000… |
… | …1110110101100000001011 |
3 | 1111010021001220212010122111 |
4 | 2210321012032311200023 |
5 | 2441123001304134011 |
6 | 40033310035403151 |
7 | 2246442140663551 |
oct | 244710616654013 |
9 | 44107056763574 |
10 | 11331302021131 |
11 | 367963a647a64 |
12 | 13300ba1534b7 |
13 | 6426ca2ac951 |
14 | 2b261ba0bbd1 |
15 | 149b46e31121 |
hex | a4e463b580b |
11331302021131 has 4 divisors (see below), whose sum is σ = 11331861308064. Its totient is φ = 11330742734200.
The previous prime is 11331302021099. The next prime is 11331302021159. The reversal of 11331302021131 is 13112020313311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331302021131 - 25 = 11331302021099 is a prime.
It is a super-3 number, since 3×113313020211313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331302051131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279613075 + ... + 279653596.
It is an arithmetic number, because the mean of its divisors is an integer number (2832965327016).
Almost surely, 211331302021131 is an apocalyptic number.
11331302021131 is a deficient number, since it is larger than the sum of its proper divisors (559286933).
11331302021131 is an equidigital number, since it uses as much as digits as its factorization.
11331302021131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 559286932.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11331302021131 its reverse (13112020313311), we get a palindrome (24443322334442).
The spelling of 11331302021131 in words is "eleven trillion, three hundred thirty-one billion, three hundred two million, twenty-one thousand, one hundred thirty-one".
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