Base | Representation |
---|---|
bin | 1010010011100100011101… |
… | …0111010100101010101011 |
3 | 1111010021010020121112111212 |
4 | 2210321013113110222223 |
5 | 2441123021140220042 |
6 | 40033311554543335 |
7 | 2246442461335166 |
oct | 244710727245253 |
9 | 44107106545455 |
10 | 11331321023147 |
11 | 367964a346504 |
12 | 1330104597b4b |
13 | 642701203a48 |
14 | 2b2620356add |
15 | 149b48936482 |
hex | a4e475d4aab |
11331321023147 has 2 divisors, whose sum is σ = 11331321023148. Its totient is φ = 11331321023146.
The previous prime is 11331321023063. The next prime is 11331321023173. The reversal of 11331321023147 is 74132012313311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331321023147 is a prime.
It is a super-2 number, since 2×113313210231472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331321223147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660511573 + 5665660511574.
It is an arithmetic number, because the mean of its divisors is an integer number (5665660511574).
Almost surely, 211331321023147 is an apocalyptic number.
11331321023147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331321023147 is an equidigital number, since it uses as much as digits as its factorization.
11331321023147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 11331321023147 its reverse (74132012313311), we get a palindrome (85463333336458).
The spelling of 11331321023147 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, twenty-three thousand, one hundred forty-seven".
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