11331321130033 has 4 divisors (see below), whose sum is σ = 11331361142640. Its totient is φ = 11331281117428.

The previous prime is 11331321129949. The next prime is 11331321130067. The reversal of 11331321130033 is 33003112313311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331321130033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331121130033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19578463 + ... + 20148916.

It is an arithmetic number, because the mean of its divisors is an integer number (2832840285660).

Almost surely, 2^{11331321130033} is an apocalyptic number.

It is an amenable number.

11331321130033 is a deficient number, since it is larger than the sum of its proper divisors (40012607).

11331321130033 is an equidigital number, since it uses as much as digits as its factorization.

11331321130033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40012606.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11331321130033 its reverse (33003112313311), we get a palindrome (44334433443344).

The spelling of 11331321130033 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, one hundred thirty thousand, thirty-three".