Base | Representation |
---|---|
bin | 10000011111010011111… |
… | …100010011110010001101 |
3 | 11000022210221010222021001 |
4 | 100133103330103302031 |
5 | 122031123320413401 |
6 | 2224315335340301 |
7 | 144603033535015 |
oct | 20372374236215 |
9 | 4008727128231 |
10 | 1133132201101 |
11 | 3a761665007a |
12 | 163737821691 |
13 | 82b140611b4 |
14 | 3cbb58ccc45 |
15 | 1e71e584601 |
hex | 107d3f13c8d |
1133132201101 has 2 divisors, whose sum is σ = 1133132201102. Its totient is φ = 1133132201100.
The previous prime is 1133132201083. The next prime is 1133132201107. The reversal of 1133132201101 is 1011022313311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 698553282025 + 434578919076 = 835795^2 + 659226^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133132201101 is a prime.
It is a super-2 number, since 2×11331322011012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133132201107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566566100550 + 566566100551.
It is an arithmetic number, because the mean of its divisors is an integer number (566566100551).
Almost surely, 21133132201101 is an apocalyptic number.
It is an amenable number.
1133132201101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133132201101 is an equidigital number, since it uses as much as digits as its factorization.
1133132201101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1133132201101 its reverse (1011022313311), we get a palindrome (2144154514412).
The spelling of 1133132201101 in words is "one trillion, one hundred thirty-three billion, one hundred thirty-two million, two hundred one thousand, one hundred one".
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