11331323131301 has 4 divisors (see below), whose sum is σ = 11331333621600. Its totient is φ = 11331312641004.

The previous prime is 11331323131199. The next prime is 11331323131309. The reversal of 11331323131301 is 10313132313311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11331323131301 - 2⁴² = 6933276620197 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331323131309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3411131 + ... + 5856488.

It is an arithmetic number, because the mean of its divisors is an integer number (2832833405400).

Almost surely, 2^{11331323131301} is an apocalyptic number.

It is an amenable number.

11331323131301 is a deficient number, since it is larger than the sum of its proper divisors (10490299).

11331323131301 is an equidigital number, since it uses as much as digits as its factorization.

11331323131301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10490298.

The product of its (nonzero) digits is 1458, while the sum is 26.

Adding to 11331323131301 its reverse (10313132313311), we get a palindrome (21644455444612).

The spelling of 11331323131301 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-three million, one hundred thirty-one thousand, three hundred one".