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11331331197 = 33777110399
BaseRepresentation
bin10101000110110011…
…00110010001111101
31002020200220021012020
422203121212101331
5141201310044242
65112221430353
7550541504004
oct124331462175
932220807166
1011331331197
11489527192a
122242a0b3b9
1310b7775304
14796cbbc3b
15464bdb6ec
hex2a366647d

11331331197 has 4 divisors (see below), whose sum is σ = 15108441600. Its totient is φ = 7554220796.

The previous prime is 11331331189. The next prime is 11331331213. The reversal of 11331331197 is 79113313311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331331197 - 23 = 11331331189 is a prime.

It is a super-2 number, since 2×113313311972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331331597) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888555197 + ... + 1888555202.

It is an arithmetic number, because the mean of its divisors is an integer number (3777110400).

Almost surely, 211331331197 is an apocalyptic number.

It is an amenable number.

11331331197 is a deficient number, since it is larger than the sum of its proper divisors (3777110403).

11331331197 is an equidigital number, since it uses as much as digits as its factorization.

11331331197 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3777110402.

The product of its digits is 5103, while the sum is 33.

The spelling of 11331331197 in words is "eleven billion, three hundred thirty-one million, three hundred thirty-one thousand, one hundred ninety-seven".

Divisors: 1 3 3777110399 11331331197