11331332113333 has 2 divisors, whose sum is σ = 11331332113334. Its totient is φ = 11331332113332.

The previous prime is 11331332113163. The next prime is 11331332113349. The reversal of 11331332113333 is 33331123313311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9262271386404 + 2069060726929 = 3043398^2 + 1438423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331332113333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331332113295 and 11331332113304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331332113133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665666056666 + 5665666056667.

It is an arithmetic number, because the mean of its divisors is an integer number (5665666056667).

Almost surely, 2^{11331332113333} is an apocalyptic number.

It is an amenable number.

11331332113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331332113333 is an equidigital number, since it uses as much as digits as its factorization.

11331332113333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13122, while the sum is 31.

Adding to 11331332113333 its reverse (33331123313311), we get a palindrome (44662455426644).

The spelling of 11331332113333 in words is "eleven trillion, three hundred thirty-one billion, three hundred thirty-two million, one hundred thirteen thousand, three hundred thirty-three".