11331401205013 has 4 divisors (see below), whose sum is σ = 11332118806848. Its totient is φ = 11330683603180.

The previous prime is 11331401205011. The next prime is 11331401205029. The reversal of 11331401205013 is 31050210413311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331401205013 - 2¹ = 11331401205011 is a prime.

It is a super-3 number, since 3×11331401205013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331401205011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358777231 + ... + 358808812.

It is an arithmetic number, because the mean of its divisors is an integer number (2833029701712).

Almost surely, 2^{11331401205013} is an apocalyptic number.

It is an amenable number.

11331401205013 is a deficient number, since it is larger than the sum of its proper divisors (717601835).

11331401205013 is an equidigital number, since it uses as much as digits as its factorization.

11331401205013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 717601834.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 11331401205013 its reverse (31050210413311), we get a palindrome (42381611618324).

The spelling of 11331401205013 in words is "eleven trillion, three hundred thirty-one billion, four hundred one million, two hundred five thousand, thirteen".