Base | Representation |
---|---|
bin | 10000011111010101010… |
… | …000010011000010000101 |
3 | 11000022212110120112221002 |
4 | 100133111100103002011 |
5 | 122031144434434432 |
6 | 2224321443303045 |
7 | 144603421634405 |
oct | 20372520230205 |
9 | 4008773515832 |
10 | 1133154218117 |
11 | 3a7628018859 |
12 | 16374307aa85 |
13 | 82b1879c70c |
14 | 3cbb87c0805 |
15 | 1e721482e62 |
hex | 107d5413085 |
1133154218117 has 2 divisors, whose sum is σ = 1133154218118. Its totient is φ = 1133154218116.
The previous prime is 1133154218113. The next prime is 1133154218137. The reversal of 1133154218117 is 7118124513311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 979929727396 + 153224490721 = 989914^2 + 391439^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133154218117 - 22 = 1133154218113 is a prime.
It is a super-2 number, since 2×11331542181172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133154218113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566577109058 + 566577109059.
It is an arithmetic number, because the mean of its divisors is an integer number (566577109059).
Almost surely, 21133154218117 is an apocalyptic number.
It is an amenable number.
1133154218117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133154218117 is an equidigital number, since it uses as much as digits as its factorization.
1133154218117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 38.
The spelling of 1133154218117 in words is "one trillion, one hundred thirty-three billion, one hundred fifty-four million, two hundred eighteen thousand, one hundred seventeen".
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