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1133154234101 is a prime number
BaseRepresentation
bin10000011111010101010…
…000010110111011110101
311000022212110121100212002
4100133111100112323311
5122031144440442401
62224321443505045
7144603422032121
oct20372520267365
94008773540762
101133154234101
113a762802986a
12163743088185
1382b187a6a86
143cbb87c6581
151e721487a6b
hex107d5416ef5

1133154234101 has 2 divisors, whose sum is σ = 1133154234102. Its totient is φ = 1133154234100.

The previous prime is 1133154234049. The next prime is 1133154234133. The reversal of 1133154234101 is 1014324513311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 745960416100 + 387193818001 = 863690^2 + 622249^2 .

It is an emirp because it is prime and its reverse (1014324513311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133154234101 - 214 = 1133154217717 is a prime.

It is a super-2 number, since 2×11331542341012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133154234151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566577117050 + 566577117051.

It is an arithmetic number, because the mean of its divisors is an integer number (566577117051).

Almost surely, 21133154234101 is an apocalyptic number.

It is an amenable number.

1133154234101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133154234101 is an equidigital number, since it uses as much as digits as its factorization.

1133154234101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1133154234101 its reverse (1014324513311), we get a palindrome (2147478747412).

The spelling of 1133154234101 in words is "one trillion, one hundred thirty-three billion, one hundred fifty-four million, two hundred thirty-four thousand, one hundred one".