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113320000193 is a prime number
BaseRepresentation
bin110100110001001100…
…1011111101011000001
3101211111110120110110012
41221202121133223001
53324034410001233
6124020344514305
711121114052211
oct1514231375301
9354443513405
10113320000193
1144071205424
1219b6677b995
13a8bc29276a
1456b00c8241
152e337eb548
hex1a6265fac1

113320000193 has 2 divisors, whose sum is σ = 113320000194. Its totient is φ = 113320000192.

The previous prime is 113320000153. The next prime is 113320000217. The reversal of 113320000193 is 391000023311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109024115344 + 4295884849 = 330188^2 + 65543^2 .

It is a cyclic number.

It is not a de Polignac number, because 113320000193 - 220 = 113318951617 is a prime.

It is a super-4 number, since 4×1133200001934 (a number of 45 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (113320000153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660000096 + 56660000097.

It is an arithmetic number, because the mean of its divisors is an integer number (56660000097).

Almost surely, 2113320000193 is an apocalyptic number.

It is an amenable number.

113320000193 is a deficient number, since it is larger than the sum of its proper divisors (1).

113320000193 is an equidigital number, since it uses as much as digits as its factorization.

113320000193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

The spelling of 113320000193 in words is "one hundred thirteen billion, three hundred twenty million, one hundred ninety-three", and thus it is an aban number.