Base | Representation |
---|---|
bin | 1010010011100111000010… |
… | …0011100111100100000011 |
3 | 1111010022220102000111101011 |
4 | 2210321300203213210003 |
5 | 2441130430100042011 |
6 | 40033504323221351 |
7 | 2246465552443654 |
oct | 244716043474403 |
9 | 44108812014334 |
10 | 11332012112131 |
11 | 3679974459927 |
12 | 1330277b17857 |
13 | 6427b1443139 |
14 | 2b268805152b |
15 | 149b89448621 |
hex | a4e708e7903 |
11332012112131 has 2 divisors, whose sum is σ = 11332012112132. Its totient is φ = 11332012112130.
The previous prime is 11332012112123. The next prime is 11332012112153. The reversal of 11332012112131 is 13121121023311.
It is an a-pointer prime, because the next prime (11332012112153) can be obtained adding 11332012112131 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332012112131 - 23 = 11332012112123 is a prime.
It is a super-2 number, since 2×113320121121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11332012112111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666006056065 + 5666006056066.
It is an arithmetic number, because the mean of its divisors is an integer number (5666006056066).
Almost surely, 211332012112131 is an apocalyptic number.
11332012112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332012112131 is an equidigital number, since it uses as much as digits as its factorization.
11332012112131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 11332012112131 its reverse (13121121023311), we get a palindrome (24453133135442).
The spelling of 11332012112131 in words is "eleven trillion, three hundred thirty-two billion, twelve million, one hundred twelve thousand, one hundred thirty-one".
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