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11332012213129 is a prime number
BaseRepresentation
bin1010010011100111000010…
…0100000000001110001001
31111010022220102012121220211
42210321300210000032021
52441130430111310004
640033504325321121
72246465553344266
oct244716044001611
944108812177824
1011332012213129
1136799745187a3
121330277b661a1
136427b147a0ba
142b268807a26d
15149b89468504
hexa4e70900389

11332012213129 has 2 divisors, whose sum is σ = 11332012213130. Its totient is φ = 11332012213128.

The previous prime is 11332012213097. The next prime is 11332012213141. The reversal of 11332012213129 is 92131221023311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7928577587529 + 3403434625600 = 2815773^2 + 1844840^2 .

It is a cyclic number.

It is not a de Polignac number, because 11332012213129 - 25 = 11332012213097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11332012213129.

It is not a weakly prime, because it can be changed into another prime (11332012213829) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666006106564 + 5666006106565.

It is an arithmetic number, because the mean of its divisors is an integer number (5666006106565).

Almost surely, 211332012213129 is an apocalyptic number.

It is an amenable number.

11332012213129 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332012213129 is an equidigital number, since it uses as much as digits as its factorization.

11332012213129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 11332012213129 in words is "eleven trillion, three hundred thirty-two billion, twelve million, two hundred thirteen thousand, one hundred twenty-nine".