Base | Representation |
---|---|
bin | 10000011111011000000… |
… | …011111110110000010101 |
3 | 11000022222202012121220121 |
4 | 100133120003332300111 |
5 | 122031244014232411 |
6 | 2224330245031541 |
7 | 144604533204502 |
oct | 20373003766025 |
9 | 4008882177817 |
10 | 1133201320981 |
11 | 3a765166a944 |
12 | 1637569b55b1 |
13 | 82b25482232 |
14 | 3cbc0b624a9 |
15 | 1e725689571 |
hex | 107d80fec15 |
1133201320981 has 2 divisors, whose sum is σ = 1133201320982. Its totient is φ = 1133201320980.
The previous prime is 1133201320967. The next prime is 1133201321003. The reversal of 1133201320981 is 1890231023311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1032357602500 + 100843718481 = 1016050^2 + 317559^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133201320981 - 215 = 1133201288213 is a prime.
It is a super-2 number, since 2×11332013209812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133201320921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566600660490 + 566600660491.
It is an arithmetic number, because the mean of its divisors is an integer number (566600660491).
Almost surely, 21133201320981 is an apocalyptic number.
It is an amenable number.
1133201320981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133201320981 is an equidigital number, since it uses as much as digits as its factorization.
1133201320981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 34.
The spelling of 1133201320981 in words is "one trillion, one hundred thirty-three billion, two hundred one million, three hundred twenty thousand, nine hundred eighty-one".
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