Base | Representation |
---|---|
bin | 110100110001001110… |
… | …0010100100011000001 |
3 | 101211111111222002201121 |
4 | 1221202130110203001 |
5 | 3324040102203212 |
6 | 124020412432241 |
7 | 11121123256156 |
oct | 1514234244301 |
9 | 354444862647 |
10 | 113320741057 |
11 | 44071671007 |
12 | 19b66a78681 |
13 | a8bc491a44 |
14 | 56b023c22d |
15 | 2e338e5d07 |
hex | 1a627148c1 |
113320741057 has 2 divisors, whose sum is σ = 113320741058. Its totient is φ = 113320741056.
The previous prime is 113320740991. The next prime is 113320741091. The reversal of 113320741057 is 750147023311.
It is an a-pointer prime, because the next prime (113320741091) can be obtained adding 113320741057 to its sum of digits (34).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96502801201 + 16817939856 = 310649^2 + 129684^2 .
It is a cyclic number.
It is not a de Polignac number, because 113320741057 - 211 = 113320739009 is a prime.
It is not a weakly prime, because it can be changed into another prime (113320741097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660370528 + 56660370529.
It is an arithmetic number, because the mean of its divisors is an integer number (56660370529).
Almost surely, 2113320741057 is an apocalyptic number.
It is an amenable number.
113320741057 is a deficient number, since it is larger than the sum of its proper divisors (1).
113320741057 is an equidigital number, since it uses as much as digits as its factorization.
113320741057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17640, while the sum is 34.
Adding to 113320741057 its reverse (750147023311), we get a palindrome (863467764368).
The spelling of 113320741057 in words is "one hundred thirteen billion, three hundred twenty million, seven hundred forty-one thousand, fifty-seven".
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