Base | Representation |
---|---|
bin | 1010010011100111010111… |
… | …0111100000100010100011 |
3 | 1111010100010121200020212021 |
4 | 2210321311313200202203 |
5 | 2441131120402243243 |
6 | 40033521225042311 |
7 | 2246501014001203 |
oct | 244716567404243 |
9 | 44110117606767 |
10 | 11332101212323 |
11 | 3679a0a786151 |
12 | 13302a1926397 |
13 | 6427c6a3b648 |
14 | 2b2695c06403 |
15 | 149b921986ed |
hex | a4e75de08a3 |
11332101212323 has 2 divisors, whose sum is σ = 11332101212324. Its totient is φ = 11332101212322.
The previous prime is 11332101212321. The next prime is 11332101212407. The reversal of 11332101212323 is 32321210123311.
11332101212323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332101212323 - 21 = 11332101212321 is a prime.
Together with 11332101212321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11332101212321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666050606161 + 5666050606162.
It is an arithmetic number, because the mean of its divisors is an integer number (5666050606162).
Almost surely, 211332101212323 is an apocalyptic number.
11332101212323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332101212323 is an equidigital number, since it uses as much as digits as its factorization.
11332101212323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11332101212323 its reverse (32321210123311), we get a palindrome (43653311335634).
The spelling of 11332101212323 in words is "eleven trillion, three hundred thirty-two billion, one hundred one million, two hundred twelve thousand, three hundred twenty-three".
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