Base | Representation |
---|---|
bin | 1101100000100… |
… | …10010010011001 |
3 | 21220020022100021 |
4 | 12300102102121 |
5 | 213002233423 |
6 | 15124510441 |
7 | 2544133153 |
oct | 660222231 |
9 | 256208307 |
10 | 113321113 |
11 | 58a6a914 |
12 | 31b4b421 |
13 | 1a628c19 |
14 | 1109bad3 |
15 | 9e3695d |
hex | 6c12499 |
113321113 has 2 divisors, whose sum is σ = 113321114. Its totient is φ = 113321112.
The previous prime is 113321107. The next prime is 113321189. The reversal of 113321113 is 311123311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112084569 + 1236544 = 10587^2 + 1112^2 .
It is an emirp because it is prime and its reverse (311123311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113321113 - 25 = 113321081 is a prime.
It is not a weakly prime, because it can be changed into another prime (113321413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660556 + 56660557.
It is an arithmetic number, because the mean of its divisors is an integer number (56660557).
Almost surely, 2113321113 is an apocalyptic number.
It is an amenable number.
113321113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113321113 is an equidigital number, since it uses as much as digits as its factorization.
113321113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54, while the sum is 16.
The square root of 113321113 is about 10645.2389827566. The cubic root of 113321113 is about 483.9163291946.
Adding to 113321113 its reverse (311123311), we get a palindrome (424444424).
The spelling of 113321113 in words is "one hundred thirteen million, three hundred twenty-one thousand, one hundred thirteen".
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