Base | Representation |
---|---|
bin | 1010010011100111011110… |
… | …1001001101110011011101 |
3 | 1111010100012200202122022012 |
4 | 2210321313221031303131 |
5 | 2441131201020114442 |
6 | 40033524212001005 |
7 | 2246501525236064 |
oct | 244716751156335 |
9 | 44110180678265 |
10 | 11332131019997 |
11 | 3679a25595097 |
12 | 13302ab900165 |
13 | 6427ccc76c18 |
14 | 2b2699b651db |
15 | 149b94ad5582 |
hex | a4e77a4dcdd |
11332131019997 has 2 divisors, whose sum is σ = 11332131019998. Its totient is φ = 11332131019996.
The previous prime is 11332131019949. The next prime is 11332131020029. The reversal of 11332131019997 is 79991013123311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9318189710041 + 2013941309956 = 3052571^2 + 1419134^2 .
It is a cyclic number.
It is not a de Polignac number, because 11332131019997 - 218 = 11332130757853 is a prime.
It is a super-2 number, since 2×113321310199972 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11332131019907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666065509998 + 5666065509999.
It is an arithmetic number, because the mean of its divisors is an integer number (5666065509999).
Almost surely, 211332131019997 is an apocalyptic number.
It is an amenable number.
11332131019997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332131019997 is an equidigital number, since it uses as much as digits as its factorization.
11332131019997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 275562, while the sum is 50.
The spelling of 11332131019997 in words is "eleven trillion, three hundred thirty-two billion, one hundred thirty-one million, nineteen thousand, nine hundred ninety-seven".
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