Base | Representation |
---|---|
bin | 10000011111011000110… |
… | …001010011011001011101 |
3 | 11000100000120120020121211 |
4 | 100133120301103121131 |
5 | 122031310034431023 |
6 | 2224331351424421 |
7 | 144605036200204 |
oct | 20373061233135 |
9 | 4010016506554 |
10 | 1133213202013 |
11 | 3a7658345282 |
12 | 16375a985111 |
13 | 82b27a82029 |
14 | 3cbc257623b |
15 | 1e726734a0d |
hex | 107d8c5365d |
1133213202013 has 2 divisors, whose sum is σ = 1133213202014. Its totient is φ = 1133213202012.
The previous prime is 1133213201983. The next prime is 1133213202041. The reversal of 1133213202013 is 3102023123311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1042363405444 + 90849796569 = 1020962^2 + 301413^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133213202013 - 213 = 1133213193821 is a prime.
It is a super-2 number, since 2×11332132020132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133213203013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566606601006 + 566606601007.
It is an arithmetic number, because the mean of its divisors is an integer number (566606601007).
Almost surely, 21133213202013 is an apocalyptic number.
It is an amenable number.
1133213202013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133213202013 is an equidigital number, since it uses as much as digits as its factorization.
1133213202013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1133213202013 its reverse (3102023123311), we get a palindrome (4235236325324).
The spelling of 1133213202013 in words is "one trillion, one hundred thirty-three billion, two hundred thirteen million, two hundred two thousand, thirteen".
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