Base | Representation |
---|---|
bin | 1010010011100111110010… |
… | …0010011110111111011111 |
3 | 1111010100102102021211210021 |
4 | 2210321330202132333133 |
5 | 2441131333031011341 |
6 | 40033540304053011 |
7 | 2246503543246225 |
oct | 244717442367737 |
9 | 44110372254707 |
10 | 11332213141471 |
11 | 3679a67985182 |
12 | 1330313304167 |
13 | 642813c9ab01 |
14 | 2b26a6a20b15 |
15 | 149b9be079d1 |
hex | a4e7c89efdf |
11332213141471 has 4 divisors (see below), whose sum is σ = 11332981285632. Its totient is φ = 11331444997312.
The previous prime is 11332213141463. The next prime is 11332213141481. The reversal of 11332213141471 is 17414131223311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11332213141471 - 23 = 11332213141463 is a prime.
It is a super-3 number, since 3×113322131414713 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11332213141481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 384049951 + ... + 384079456.
It is an arithmetic number, because the mean of its divisors is an integer number (2833245321408).
Almost surely, 211332213141471 is an apocalyptic number.
11332213141471 is a deficient number, since it is larger than the sum of its proper divisors (768144161).
11332213141471 is an equidigital number, since it uses as much as digits as its factorization.
11332213141471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 768144160.
The product of its digits is 12096, while the sum is 34.
Adding to 11332213141471 its reverse (17414131223311), we get a palindrome (28746344364782).
The spelling of 11332213141471 in words is "eleven trillion, three hundred thirty-two billion, two hundred thirteen million, one hundred forty-one thousand, four hundred seventy-one".
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